A cunning little optical trick to get us started - how does the triangle lose a square of area yet keep its overall dimensions? Best explained answer by the end of June wins the prize...

the red triangle is longer and higher than the blue one so when you put the blue triangle at the front and the red triangle on top but if you don't move the yellow and green shape it will be to short and to high. so you move the yellow one from on top then move it one square to the left. this means that it doesn't lose any dimention.

the answer is simple the sides of the triangles are different so wen u put a long side in stead of short you lose some of the area in this case the blue triangle has been put covering its shortest side and the red covering its longest. so the bottom one has lost 1/2mm squared. This may not be a good explination but i know what im talking about

The key to the puzzle is the fact that neither of the 13x5 "triangles" has the same area as its component parts.

The four figures (the yellow, red, blue and green shapes) total 32 units of area, but the triangles are 13 wide and 5 tall, which equals 32.5 units. The blue triangle has a ratio of 5:2, while the red triangle has the ratio 8:3, and these are not the same ratio. So the apparent combined hypotenuse in each figure is actually bent.

## 5 Comments:

the red triangle is longer and higher than the blue one so when you put the blue triangle at the front and the red triangle on top but if you don't move the yellow and green shape it will be to short and to high. so you move the yellow one from on top then move it one square to the left. this means that it doesn't lose any dimention.

by le thanh hoang 8cc

the answer is simple the sides of the triangles are different so wen u put a long side in stead of short you lose some of the area in this case the blue triangle has been put covering its shortest side and the red covering its longest. so the bottom one has lost 1/2mm squared. This may not be a good explination but i know what im talking about

The key to the puzzle is the fact that neither of the 13x5 "triangles" has the same area as its component parts.

The four figures (the yellow, red, blue and green shapes) total 32 units of area, but the triangles are 13 wide and 5 tall, which equals 32.5 units. The blue triangle has a ratio of 5:2, while the red triangle has the ratio 8:3, and these are not the same ratio. So the apparent combined hypotenuse in each figure is actually bent.

Weirdddddddthere is a white sqaure on the bottom row (the white squares are in the background)thats the missing square

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